To implement the expression X'Y'Z'+X'YZ'+XY'Z+X'YZ+XYZ' , it takesGroup of answer choicesfive AND gates, three OR gates, and seven invertersfour AND gates, two OR gates, and six invertersfive AND gates, one OR gate, and eight invertersfive AND gates, one OR gate, and seven inverters
Question
To implement the expression X'Y'Z'+X'YZ'+XY'Z+X'YZ+XYZ' , it takesGroup of answer choicesfive AND gates, three OR gates, and seven invertersfour AND gates, two OR gates, and six invertersfive AND gates, one OR gate, and eight invertersfive AND gates, one OR gate, and seven inverters
Solution
The expression X'Y'Z'+X'YZ'+XY'Z+X'YZ+XYZ' can be implemented using five AND gates, one OR gate, and seven inverters.
Here's the step-by-step breakdown:
-
Inverters: You need an inverter for each variable that has a prime (') after it. In this case, you have X' three times, Y' twice, and Z' twice. So, you need 3+2+2 = 7 inverters.
-
AND gates: Each term in the expression is a product (AND operation) of three variables. Since there are five terms, you need five AND gates.
-
OR gates: The entire expression is a sum (OR operation) of the five terms. Therefore, you need one OR gate to combine these terms.
So, the correct answer is "five AND gates, one OR gate, and seven inverters".
Similar Questions
To implement the expression X'Y'Z'+X'YZ'+XY'Z+X'YZ+XYZ' , it takes
obtain the truth table of xy+y'z+x'y'+x'z and then implement the function using logic gates
(X+Y’)(X+Z) can be represented by _____*(X+Y’Z)(Y+X’)XY’(X+Z’)
The Boolean expression x'y+yz+xz can be reduced toa.x'y+xzb.x'y+yz+xzc.x'y+yzd.yz+xz
How many basic logic gates are there? Question 3Answera.2 b.3 c.4 d.5
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.