The number in the unit's place of 999^22292582 is 1.

Here's the step by step explanation:

1. First, we need to understand the cyclicity of 9. The cyclicity of 9 is 2, which means the last digit repeats every 2 powers. The cycle is {9,1}.

2. Then, we need to find the remainder when the power (22292582) is divided by the cyclicity (2). The remainder is 0.

3. Since the remainder is 0, we take the last number in the cycle of 9, which is 1.

So, the number in the unit’s place of 999^22292582 is 1.

Question

The number in the unit's place of 999^22292582 is 1.

Here's the step by step explanation:

1. First, we need to understand the cyclicity of 9. The cyclicity of 9 is 2, which means the last digit repeats every 2 powers. The cycle is {9,1}.

2. Then, we need to find the remainder when the power (22292582) is divided by the cyclicity (2). The remainder is 0.

3. Since the remainder is 0, we take the last number in the cycle of 9, which is 1.

So, the number in the unit’s place of 999^22292582 is 1.

Knowee AI · Accepted Answer

The number in the unit's place of 999^22292582 is 1.

Here's the step by step explanation:

1. First, we need to understand the cyclicity of 9. The cyclicity of 9 is 2, which means the last digit repeats every 2 powers. The cycle is {9,1}.

2. Then, we need to find the remainder when the power (22292582) is divided by the cyclicity (2). The remainder is 0.

3. Since the remainder is 0, we take the last number in the cycle of 9, which is 1.

So, the number in the unit’s place of 999^22292582 is 1.

What is the number in the unit’s place of 999^22292582Options :9371Clear ResponsePreviousFlagNextEnd Test