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[48] Given that x = – 2 is a solution to 𝑥2+𝑏𝑥–6=0,x 2 +bx–6=0, which of the following polynomials is a factor of 𝑥2+𝑏𝑥–6?x 2 +bx–6?

Question

[48] Given that x = – 2 is a solution to 𝑥2+𝑏𝑥–6=0,x 2 +bx–6=0, which of the following polynomials is a factor of 𝑥2+𝑏𝑥–6?x 2 +bx–6?

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Solution

Given that x = -2 is a solution to the equation x^2 + bx - 6 = 0, we can use the fact that if a number is a solution to a polynomial equation, then the corresponding binomial is a factor of the polynomial.

The binomial corresponding to x = -2 is (x + 2), because if we set x + 2 = 0, we get x = -2.

Therefore, (x + 2) is a factor of the polynomial x^2 + bx - 6.

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