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The table gives a set of outcomes and their probabilities. Let A be the event "the outcome is a divisor of 10". Find P(A).Outcome Probability1 0.012 0.123 0.224 0.315 0.246 0.037 0.018 0.039 0.0210 0.01Submit

Question

The table gives a set of outcomes and their probabilities. Let A be the event "the outcome is a divisor of 10". Find P(A).Outcome Probability1 0.012 0.123 0.224 0.315 0.246 0.037 0.018 0.039 0.0210 0.01Submit

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Solution

The divisors of 10 are 1, 2, 5, and 10.

From the table, we can see that the probabilities of these outcomes are:

  • The probability of 1 is 0.01
  • The probability of 2 is 0.12
  • The probability of 5 is 0.24
  • The probability of 10 is 0.01

To find the probability of event A, which is the event that the outcome is a divisor of 10, we add up these probabilities.

So, P(A) = P(1) + P(2) + P(5) + P(10) = 0.01 + 0.12 + 0.24 + 0.01 = 0.38.

Therefore, the probability of event A is 0.38.

This problem has been solved

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