It seems like you've missed out on providing the actual equation. However, I can guide you on how to solve a general exponential equation of the form 2e^x = 40.

(a) First, we isolate e^x by dividing both sides of the equation by 2. This gives us:

e^x = 40 / 2
e^x = 20

(b) Next, we take the natural logarithm (ln) of both sides to get rid of the base e on the left side. This gives us:

ln(e^x) = ln(20)

Using the property of logarithms that ln(a^b) = b*ln(a), we can simplify the left side to:

x = ln(20)

So, the solution to the equation 2e^x = 40 is x = ln(20).

Question

It seems like you've missed out on providing the actual equation. However, I can guide you on how to solve a general exponential equation of the form 2e^x = 40.

(a) First, we isolate e^x by dividing both sides of the equation by 2. This gives us:

e^x = 40 / 2
e^x = 20

(b) Next, we take the natural logarithm (ln) of both sides to get rid of the base e on the left side. This gives us:

ln(e^x) = ln(20)

Using the property of logarithms that ln(a^b) = b*ln(a), we can simplify the left side to:

x = ln(20)

So, the solution to the equation 2e^x = 40 is x = ln(20).

Knowee AI · Accepted Answer

It seems like you've missed out on providing the actual equation. However, I can guide you on how to solve a general exponential equation of the form 2e^x = 40.

(a) First, we isolate e^x by dividing both sides of the equation by 2. This gives us:

e^x = 40 / 2
e^x = 20

(b) Next, we take the natural logarithm (ln) of both sides to get rid of the base e on the left side. This gives us:

ln(e^x) = ln(20)

Using the property of logarithms that ln(a^b) = b*ln(a), we can simplify the left side to:

x = ln(20)

So, the solution to the equation 2e^x = 40 is x = ln(20).

Let's solve the exponential equation 2ex = 40.(a) First, we isolate ex to get the equivalent equation .(b) Next, we take ln of each side to get the equivalent equation

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