Find the solution of the system of equations.minus, 2, x, minus, 2, y, equals, 0−2x−2y=0minus, x, plus, 4, y, equals, 40−x+4y=40
Question
Find the solution of the system of equations.minus, 2, x, minus, 2, y, equals, 0−2x−2y=0minus, x, plus, 4, y, equals, 40−x+4y=40
Solution
Sure, let's solve the system of equations step by step.
The system of equations is:
-2x - 2y = 0 -x + 4y = 40
Step 1: Simplify the equations if possible. The first equation can be simplified by dividing all terms by -2:
x + y = 0
So now we have:
x + y = 0 -x + 4y = 40
Step 2: Solve one of the equations for one variable. The first equation can be solved for x:
x = -y
Step 3: Substitute the expression from step 2 into the other equation. Substituting x = -y into the second equation gives:
-(-y) + 4y = 40 y + 4y = 40 5y = 40
Step 4: Solve for y. Dividing both sides of the equation by 5 gives:
y = 8
Step 5: Substitute y = 8 into the first equation to solve for x:
x + 8 = 0 x = -8
So the solution to the system of equations is x = -8, y = 8.
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