Let's denote the side of the cube as x.

The volume of the cube is x^3.

The volume of the new rectangular solid is (x+1)(x-1)x = x^3 - x.

According to the problem, the volume of the new rectangular solid is 5 less than that of the cube. So we can set up the following equation:

x^3 - x = x^3 - 5.

Solving this equation gives x = 5.

So, the volume of the cube is 5^3 = 125.

Question

Let's denote the side of the cube as x.

The volume of the cube is x^3.

The volume of the new rectangular solid is (x+1)(x-1)x = x^3 - x.

According to the problem, the volume of the new rectangular solid is 5 less than that of the cube. So we can set up the following equation:

x^3 - x = x^3 - 5.

Solving this equation gives x = 5.

So, the volume of the cube is 5^3 = 125.

Knowee AI · Accepted Answer

Let's denote the side of the cube as x.

The volume of the cube is x^3.

The volume of the new rectangular solid is (x+1)(x-1)x = x^3 - x.

According to the problem, the volume of the new rectangular solid is 5 less than that of the cube. So we can set up the following equation:

x^3 - x = x^3 - 5.

Solving this equation gives x = 5.

So, the volume of the cube is 5^3 = 125.

One dimension of a cube is increased by 1, another is decreased by 1, and the third is left unchanged. The volume of the new rectangular solid is 5 less than that of the cube. What was the volume of the cube?