To solve this problem, we need to break it down into two parts: horizontal and vertical motion. However, since we're only interested in the time it takes for the body to hit the ground, we only need to consider the vertical motion.

Step 1: Determine the vertical component of the initial velocity.

The vertical component of the velocity can be found using the equation V = V0 * sin(θ), where V0 is the initial velocity and θ is the angle of projection.

So, V = 9.8 m/s * sin(30°) = 4.9 m/s.

Step 2: Use the equation of motion to find the time it takes for the body to hit the ground.

The equation of motion is given by h = V0*t + 0.5*g*t^2, where h is the height, V0 is the initial vertical velocity, g is the acceleration due to gravity (9.8 m/s^2), and t is the time.

Rearranging the equation to solve for t gives us t = (h - 0.5*g*t^2) / V0.

Substituting the given values into the equation gives us t = (29.4 m - 0.5*9.8 m/s^2*t^2) / 4.9 m/s.

Solving this equation for t gives us t = 2 s.

So, the body will hit the ground after 2 seconds. The correct answer is A: 2 s.

Question

To solve this problem, we need to break it down into two parts: horizontal and vertical motion. However, since we're only interested in the time it takes for the body to hit the ground, we only need to consider the vertical motion.

Step 1: Determine the vertical component of the initial velocity.

The vertical component of the velocity can be found using the equation V = V0 * sin(θ), where V0 is the initial velocity and θ is the angle of projection.

So, V = 9.8 m/s * sin(30°) = 4.9 m/s.

Step 2: Use the equation of motion to find the time it takes for the body to hit the ground.

The equation of motion is given by h = V0*t + 0.5*g*t^2, where h is the height, V0 is the initial vertical velocity, g is the acceleration due to gravity (9.8 m/s^2), and t is the time.

Rearranging the equation to solve for t gives us t = (h - 0.5*g*t^2) / V0.

Substituting the given values into the equation gives us t = (29.4 m - 0.5*9.8 m/s^2*t^2) / 4.9 m/s.

Solving this equation for t gives us t = 2 s.

So, the body will hit the ground after 2 seconds. The correct answer is A: 2 s.

Knowee AI · Accepted Answer

To solve this problem, we need to break it down into two parts: horizontal and vertical motion. However, since we're only interested in the time it takes for the body to hit the ground, we only need to consider the vertical motion.

Step 1: Determine the vertical component of the initial velocity.

The vertical component of the velocity can be found using the equation V = V0 * sin(θ), where V0 is the initial velocity and θ is the angle of projection.

So, V = 9.8 m/s * sin(30°) = 4.9 m/s.

Step 2: Use the equation of motion to find the time it takes for the body to hit the ground.

The equation of motion is given by h = V0*t + 0.5*g*t^2, where h is the height, V0 is the initial vertical velocity, g is the acceleration due to gravity (9.8 m/s^2), and t is the time.

Rearranging the equation to solve for t gives us t = (h - 0.5*g*t^2) / V0.

Substituting the given values into the equation gives us t = (29.4 m - 0.5*9.8 m/s^2*t^2) / 4.9 m/s.

Solving this equation for t gives us t = 2 s.

So, the body will hit the ground after 2 seconds. The correct answer is A: 2 s.

A body is projected downward at an angle of 30° to the horizontal with a velocity of 9.8 m/s from the top of a tower 29.4 m high. How long will it take before striking the ground?A 2 s B 5 s C 8 s D 10 s

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