. Mr. R. K. Nair gets Rs. 6455 at the end of one year at the rate of 14% per annum in a recurringdeposit account. Find the monthly installment.
Question
. Mr. R. K. Nair gets Rs. 6455 at the end of one year at the rate of 14% per annum in a recurringdeposit account. Find the monthly installment.
Solution
To solve this problem, we need to use the formula for the amount in a recurring deposit account, which is:
A = P * [n(n+1)/2] * r/12/100 + P*n
Where: A = the total amount after n months P = the monthly installment n = the number of months r = the rate of interest per annum
In this case, we know that A = Rs. 6455, n = 12 months (since it's one year), and r = 14% per annum. We need to find P.
Substituting the known values into the formula, we get:
6455 = P * [12(12+1)/2] * 14/12/100 + P*12
Solving this equation will give us the value of P, which is the monthly installment.
Let's simplify the equation:
6455 = P * [78] * 14/12/100 + P12 6455 = P * 7.8 + P12 6455 = P * 19.8
Now, divide both sides of the equation by 19.8 to solve for P:
P = 6455 / 19.8 P = Rs. 326 approximately
So, the monthly installment Mr. R. K. Nair needs to pay is approximately Rs. 326.
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