At high frequency in a capacitive circuit, the current will be high. This is because the impedance (opposition to current) in a capacitive circuit decreases with increasing frequency.

Here are the steps to understand this:

1. The formula for capacitive reactance (Xc), which is the opposition to current in a capacitive circuit, is Xc = 1/(2πfC), where f is the frequency and C is the capacitance.

2. From this formula, you can see that as the frequency (f) increases, the capacitive reactance (Xc) decreases.

3. Ohm's law states that the current (I) is equal to the voltage (V) divided by the resistance (R). In AC circuits, we use impedance (Z) instead of resistance, and capacitive reactance is a form of impedance. So, I = V/Z.

4. Therefore, as the capacitive reactance (Xc) decreases, the current (I) increases, assuming the voltage (V) remains constant.

So, in a capacitive circuit, as the frequency increases, the current also increases.

Question

At high frequency in a capacitive circuit, the current will be high. This is because the impedance (opposition to current) in a capacitive circuit decreases with increasing frequency.

Here are the steps to understand this:

1. The formula for capacitive reactance (Xc), which is the opposition to current in a capacitive circuit, is Xc = 1/(2πfC), where f is the frequency and C is the capacitance.

2. From this formula, you can see that as the frequency (f) increases, the capacitive reactance (Xc) decreases.

3. Ohm's law states that the current (I) is equal to the voltage (V) divided by the resistance (R). In AC circuits, we use impedance (Z) instead of resistance, and capacitive reactance is a form of impedance. So, I = V/Z.

4. Therefore, as the capacitive reactance (Xc) decreases, the current (I) increases, assuming the voltage (V) remains constant.

So, in a capacitive circuit, as the frequency increases, the current also increases.

Knowee AI · Accepted Answer

At high frequency in a capacitive circuit, the current will be high. This is because the impedance (opposition to current) in a capacitive circuit decreases with increasing frequency.

Here are the steps to understand this:

1. The formula for capacitive reactance (Xc), which is the opposition to current in a capacitive circuit, is Xc = 1/(2πfC), where f is the frequency and C is the capacitance.

2. From this formula, you can see that as the frequency (f) increases, the capacitive reactance (Xc) decreases.

3. Ohm's law states that the current (I) is equal to the voltage (V) divided by the resistance (R). In AC circuits, we use impedance (Z) instead of resistance, and capacitive reactance is a form of impedance. So, I = V/Z.

4. Therefore, as the capacitive reactance (Xc) decreases, the current (I) increases, assuming the voltage (V) remains constant.

So, in a capacitive circuit, as the frequency increases, the current also increases.

At high frequency in a capacitive circuit, the current will be

Question

Solution

Similar Questions

Upgrade your grade with Knowee