In 1990, Walter Arfeuille of Belgium lifted a 281.5kg object through a distance of 17.1cm using only his teeth.(a) How much work was done on the object by Arfeuille in this lift, assuming the objectwas lifted at constant speed?(b) What total force was exerted on Arfeuille’s teeth during the lift?

(a) To calculate the work done by Walter Arfeuille, we can use the formula:

Work = Force x Distance

Given that the distance is 17.1 cm, we need to convert it to meters by dividing it by 100:

Distance = 17.1 cm / 100 = 0.171 m

Now, we need to find the force exerted by Arfeuille. Since the object was lifted at a constant speed, the force applied is equal to the weight of the object. The weight can be calculated using the formula:

Weight = Mass x Gravity

Given that the object's weight is 281.5 kg, we can calculate the force:

Force = Weight = 281.5 kg x 9.8 m/s^2 = 2758.7 N

Now, we can calculate the work done:

Work = Force x Distance = 2758.7 N x 0.171 m = 472.1 J

Therefore, Walter Arfeuille did 472.1 Joules of work on the object during the lift.

(b) To find the total force exerted on Arfeuille's teeth during the lift, we need to consider that the force exerted by the object is equal in magnitude but opposite in direction to the force exerted on Arfeuille's teeth.

So, the total force exerted on Arfeuille's teeth is also 2758.7 N.