Select the correct answerWhat will be the output of the following Python code?import rep = 'abc123 xyz789 lmn-22 def456'print(re.sub(r'\b([a-z]+)(\d+)', r'\2\1:', p))Options‘456def: lmn-22: 789xyz: 123abc’‘abc123: xyz789: lmn-22: def456’‘abc123:’, ‘xyz789:’, ‘lmn-22:’, ‘def456:’‘123abc: 789xyz: lmn-22 456def:’

The correct answer is ‘123abc: 789xyz: lmn-22 456def:’.

Here's the step by step explanation:

1. The Python code is using the 're' module, which provides support for regular expressions in Python.

2. The 're.sub' function is used to replace parts of a string. It takes three arguments: the pattern to search for, the pattern to replace it with, and the string to perform this operation on.

3. The pattern r'\b([a-z]+)(\d+)' is looking for words that start with one or more lowercase letters ([a-z]+), followed by one or more digits (\d+).

4. The replacement pattern r'\2\1:' is saying to replace the found pattern with the second group (\2, which is the digits), followed by the first group (\1, which is the letters), followed by a colon.

5. So, for each word in the string 'p' that matches the pattern, it's replaced by the digits first, then the letters, then a colon.

6. The output is therefore ‘123abc: 789xyz: lmn-22 456def:’. The 'lmn-22' part of the string is not affected because it doesn't match the pattern (it doesn't end with one or more digits).