This problem can be solved using the principle of conservation of momentum. The total momentum before the event (the big fish swallowing the small fish) must be equal to the total momentum after the event.

Step 1: Calculate the total momentum before the event.
The momentum of an object is given by the product of its mass and velocity. The small fish is at rest, so its momentum is 0. The big fish has a mass of 5 kg and a velocity of 1 m/s, so its momentum is 5 kg * 1 m/s = 5 kg*m/s.

Step 2: Calculate the total momentum after the event.
After the big fish swallows the small fish, they move together as a single object with a combined mass of 5 kg + 1 kg = 6 kg. We'll call the velocity of this combined object v. The total momentum after the event is therefore 6 kg * v.

Step 3: Set the total momentum before the event equal to the total momentum after the event and solve for v.
5 kg*m/s = 6 kg * v
v = 5 kg*m/s / 6 kg = 0.83 m/s

So, the velocity of the larger fish immediately after swallowing the smaller fish is 0.83 m/s.

Question

This problem can be solved using the principle of conservation of momentum. The total momentum before the event (the big fish swallowing the small fish) must be equal to the total momentum after the event.

Step 1: Calculate the total momentum before the event.
The momentum of an object is given by the product of its mass and velocity. The small fish is at rest, so its momentum is 0. The big fish has a mass of 5 kg and a velocity of 1 m/s, so its momentum is 5 kg * 1 m/s = 5 kg*m/s.

Step 2: Calculate the total momentum after the event.
After the big fish swallows the small fish, they move together as a single object with a combined mass of 5 kg + 1 kg = 6 kg. We'll call the velocity of this combined object v. The total momentum after the event is therefore 6 kg * v.

Step 3: Set the total momentum before the event equal to the total momentum after the event and solve for v.
5 kg*m/s = 6 kg * v
v = 5 kg*m/s / 6 kg = 0.83 m/s

So, the velocity of the larger fish immediately after swallowing the smaller fish is 0.83 m/s.

Knowee AI · Accepted Answer

This problem can be solved using the principle of conservation of momentum. The total momentum before the event (the big fish swallowing the small fish) must be equal to the total momentum after the event.

Step 1: Calculate the total momentum before the event.
The momentum of an object is given by the product of its mass and velocity. The small fish is at rest, so its momentum is 0. The big fish has a mass of 5 kg and a velocity of 1 m/s, so its momentum is 5 kg * 1 m/s = 5 kg*m/s.

Step 2: Calculate the total momentum after the event.
After the big fish swallows the small fish, they move together as a single object with a combined mass of 5 kg + 1 kg = 6 kg. We'll call the velocity of this combined object v. The total momentum after the event is therefore 6 kg * v.

Step 3: Set the total momentum before the event equal to the total momentum after the event and solve for v.
5 kg*m/s = 6 kg * v
v = 5 kg*m/s / 6 kg = 0.83 m/s

So, the velocity of the larger fish immediately after swallowing the smaller fish is 0.83 m/s.

A 5-kg big fish is swimming at 1 m/s towards a 1-kg small fish at rest as shown in Figure 4. What is the velocity of the larger fish immediately after swallowing the smaller fish for lunch? Ignore the effects of water resistance (Hewitt, 2015).

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