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A compound P is taken in a flat bottomed flask as shown in figure. Dilute hydrochloric acid is added drop by drop. A gas Q is evolved which is then passed in a test tube containing R. A solid precipitate S is formed. R is frequently used in white washing. During white washing a layer of R is applied on the wall and it reacts with gas Q (present in air) to produce white shiny layer of S on the wall. P, Q, R and S respectively are :  P Q R S(1) Na2SO4 SO2 Ca(OH)2 CaSO4(2) Na2SO3 O2 Ca(OH)2 CaO(3) Na2CO3 O2 Ca(OH)2 CaCO3(4) Na2CO3 CO2 Ca(OH)2 CaCO31234

Question

A compound P is taken in a flat bottomed flask as shown in figure. Dilute hydrochloric acid is added drop by drop. A gas Q is evolved which is then passed in a test tube containing R. A solid precipitate S is formed. R is frequently used in white washing. During white washing a layer of R is applied on the wall and it reacts with gas Q (present in air) to produce white shiny layer of S on the wall. P, Q, R and S respectively are :  P Q R S(1) Na2SO4 SO2 Ca(OH)2 CaSO4(2) Na2SO3 O2 Ca(OH)2 CaO(3) Na2CO3 O2 Ca(OH)2 CaCO3(4) Na2CO3 CO2 Ca(OH)2 CaCO31234

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Solution

The correct answer is (4) Na2CO3, CO2, Ca(OH)2, CaCO3.

Here's the step by step explanation:

  1. The compound P is Na2CO3 (Sodium Carbonate). When it reacts with dilute hydrochloric acid, it produces a gas Q which is CO2 (Carbon Dioxide).

  2. This gas Q (CO2) is then passed into a test tube containing R which is Ca(OH)2 (Calcium Hydroxide), frequently used in white washing.

  3. When R (Ca(OH)2) reacts with Q (CO2), it forms a solid precipitate S which is CaCO3 (Calcium Carbonate). This is the shiny white layer that forms on the wall during white washing.

So, P is Na2CO3, Q is CO2, R is Ca(OH)2 and S is CaCO3.

This problem has been solved

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