What will the following code output?#include <stdio.h>int main() {    int arr[3] = {1, 2, 3};    int *p = arr;    printf("%d\n", *(p + 2));    return 0;}

The code will output "3".

Here's the step-by-step explanation:

1. An integer array arr of size 3 is declared and initialized with the values 1, 2, and 3.

2. A pointer p is declared and initialized to point to the first element of the array arr.

3. The printf function is called to print the value of the element at the address (p + 2). In C, when you add an integer to a pointer, it advances by that many elements in the array. So, p + 2 points to the third element of the array arr.

4. *(p + 2) dereferences the pointer (p + 2), which means it gives the value stored at the address (p + 2). This is the third element of the array arr, which is 3.

5. So, the output of the program is "3".