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The grades on a French language exam are roughly normal with mean of 61 and standard deviation of 3.5. Taj scored 78 on the exam. Find the z-score for Taj’s exam grade. (if needed round your answer to 2 decimal places.)

Question

The grades on a French language exam are roughly normal with mean of 61 and standard deviation of 3.5. Taj scored 78 on the exam. Find the z-score for Taj’s exam grade. (if needed round your answer to 2 decimal places.)

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Solution

The z-score is a measure of how many standard deviations an element is from the mean. It can be calculated using the following formula:

Z = (X - μ) / σ

where: X is the value from the dataset, μ is the population mean, and σ is the standard deviation.

Given that the mean (μ) is 61, the standard deviation (σ) is 3.5, and Taj's score (X) is 78, we can substitute these values into the formula:

Z = (78 - 61) / 3.5

Calculating the above expression gives us:

Z = 17 / 3.5 = 4.86

Rounding to two decimal places, the z-score for Taj’s exam grade is 4.86. This means that Taj's score was 4.86 standard deviations above the mean.

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