Step 1: Identify the total number of balls. We have 2 red, 3 green, and 2 blue balls, which gives us a total of 7 balls.

Step 2: Identify the total number of ways to draw 2 balls from 7. This is a combination problem, which can be solved using the combination formula nCr = n! / r!(n-r)!. Here, n is the total number of balls (7) and r is the number of balls drawn (2). So, 7C2 = 7! / 2!(7-2)! = 21.

Step 3: Identify the total number of ways to draw 2 balls that are not blue. Since there are 5 balls that are not blue (2 red and 3 green), the number of ways to draw 2 balls from these 5 is 5C2 = 5! / 2!(5-2)! = 10.

Step 4: The probability that none of the balls drawn is blue is the number of ways to draw 2 balls that are not blue divided by the total number of ways to draw 2 balls. So, the probability is 10 / 21 = 0.4762 or 47.62% when expressed as a percentage.

Question

Step 1: Identify the total number of balls. We have 2 red, 3 green, and 2 blue balls, which gives us a total of 7 balls.

Step 2: Identify the total number of ways to draw 2 balls from 7. This is a combination problem, which can be solved using the combination formula nCr = n! / r!(n-r)!. Here, n is the total number of balls (7) and r is the number of balls drawn (2). So, 7C2 = 7! / 2!(7-2)! = 21.

Step 3: Identify the total number of ways to draw 2 balls that are not blue. Since there are 5 balls that are not blue (2 red and 3 green), the number of ways to draw 2 balls from these 5 is 5C2 = 5! / 2!(5-2)! = 10.

Step 4: The probability that none of the balls drawn is blue is the number of ways to draw 2 balls that are not blue divided by the total number of ways to draw 2 balls. So, the probability is 10 / 21 = 0.4762 or 47.62% when expressed as a percentage.

Knowee AI · Accepted Answer

Step 1: Identify the total number of balls. We have 2 red, 3 green, and 2 blue balls, which gives us a total of 7 balls.

Step 2: Identify the total number of ways to draw 2 balls from 7. This is a combination problem, which can be solved using the combination formula nCr = n! / r!(n-r)!. Here, n is the total number of balls (7) and r is the number of balls drawn (2). So, 7C2 = 7! / 2!(7-2)! = 21.

Step 3: Identify the total number of ways to draw 2 balls that are not blue. Since there are 5 balls that are not blue (2 red and 3 green), the number of ways to draw 2 balls from these 5 is 5C2 = 5! / 2!(5-2)! = 10.

Step 4: The probability that none of the balls drawn is blue is the number of ways to draw 2 balls that are not blue divided by the total number of ways to draw 2 balls. So, the probability is 10 / 21 = 0.4762 or 47.62% when expressed as a percentage.

14) A bag contains 2 red, 3 green and 2 blue balls. Two balls are drawn at random. What is the probability that none of the balls drawn is blue?

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