Consider the below code snippet and determine the output.class Student{ private int studentId; private float average;}class Test{ public static void main(String a[]) { Student s=new Student(); s.studentId=123; System.out.println(s.studentId); }}Select one:a.Compile time errorb.1c.0d.Any value
Question
Consider the below code snippet and determine the output.class Student{ private int studentId; private float average;}class Test{ public static void main(String a[]) { Student s=new Student(); s.studentId=123; System.out.println(s.studentId); }}Select one:a.Compile time errorb.1c.0d.Any value
Solution
The correct answer is a. Compile time error.
The reason is that the variables studentId and average in the Student class are declared as private. Private variables are only accessible within the same class, so trying to access or modify them from outside the class, as is attempted in the Test class, will result in a compile time error.
Here's the step by step explanation:
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The Student class is defined with two private variables: studentId (an integer) and average (a float).
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The Test class is defined with a main method, which is the entry point for any Java application.
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Inside the main method, a new Student object 's' is created.
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The code then tries to assign the value 123 to the studentId of the Student object 's'. However, because studentId is a private variable in the Student class, this line of code is not allowed, and will cause a compile time error.
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The next line of code, which tries to print the studentId of the Student object 's', will also cause a compile time error for the same reason.
So, the code will not compile, and no output will be produced.
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