The answer is d) stack.

Here is the step by step explanation:

1. When a subroutine is called in a program, the system needs to know where to return after executing that subroutine.

2. The CALL instruction is used to call a subroutine. The address of the instruction following the CALL instruction is the return address, because that's where the program should continue executing after the subroutine is finished.

3. This return address is stored on the stack, a special area in memory that is used for storing temporary data like this.

4. The stack is a LIFO (Last In, First Out) structure, which means that the last address stored is the first one to be retrieved. This is perfect for subroutines, because they can be nested: you can call a subroutine from within another subroutine, and the program will still remember the correct order of return addresses.

5. Therefore, when the subroutine is finished, the system will pop the return address from the stack and continue execution from there.

So, the address of the instruction following the CALL instruction is stored on the stack.

Question

The answer is d) stack.

Here is the step by step explanation:

1. When a subroutine is called in a program, the system needs to know where to return after executing that subroutine.

2. The CALL instruction is used to call a subroutine. The address of the instruction following the CALL instruction is the return address, because that's where the program should continue executing after the subroutine is finished.

3. This return address is stored on the stack, a special area in memory that is used for storing temporary data like this.

4. The stack is a LIFO (Last In, First Out) structure, which means that the last address stored is the first one to be retrieved. This is perfect for subroutines, because they can be nested: you can call a subroutine from within another subroutine, and the program will still remember the correct order of return addresses.

5. Therefore, when the subroutine is finished, the system will pop the return address from the stack and continue execution from there.

So, the address of the instruction following the CALL instruction is stored on the stack.

Knowee AI · Accepted Answer

The answer is d) stack.

Here is the step by step explanation:

1. When a subroutine is called in a program, the system needs to know where to return after executing that subroutine.

2. The CALL instruction is used to call a subroutine. The address of the instruction following the CALL instruction is the return address, because that's where the program should continue executing after the subroutine is finished.

3. This return address is stored on the stack, a special area in memory that is used for storing temporary data like this.

4. The stack is a LIFO (Last In, First Out) structure, which means that the last address stored is the first one to be retrieved. This is perfect for subroutines, because they can be nested: you can call a subroutine from within another subroutine, and the program will still remember the correct order of return addresses.

5. Therefore, when the subroutine is finished, the system will pop the return address from the stack and continue execution from there.

So, the address of the instruction following the CALL instruction is stored on the stack.

When a subroutine is called, the address of the instruction following the CALL instruction is stored in/on the a) stack pointerb) accumulatorc) program counterd) stack

Question

Solution

Similar Questions

Upgrade your grade with Knowee