Two syringes filled with water are connected by a tube. The first syringe has a plunger with an area of 3 cm2, and the second syringe has a plunger with an area of 6 cm2. If a force of 10 N is applied to the first syringe, what force acts on the plunger of the second syringe?A.3 NB.5 NC.10 ND.20 N
Question
Two syringes filled with water are connected by a tube. The first syringe has a plunger with an area of 3 cm2, and the second syringe has a plunger with an area of 6 cm2. If a force of 10 N is applied to the first syringe, what force acts on the plunger of the second syringe?A.3 NB.5 NC.10 ND.20 N
Solution
This problem can be solved using Pascal's principle, which states that when a change in pressure is applied to an enclosed fluid, it is transmitted undiminished to all portions of the fluid and to the walls of its container.
Step 1: Calculate the pressure in the first syringe using the formula Pressure = Force/Area.
Force = 10 N Area = 3 cm^2 = 3 * 10^-4 m^2 (since 1 cm^2 = 10^-4 m^2)
Pressure = 10 N / 3 * 10^-4 m^2 = 33333.33 Pa (Pascal)
Step 2: Calculate the force in the second syringe using the formula Force = Pressure * Area.
Area = 6 cm^2 = 6 * 10^-4 m^2
Force = 33333.33 Pa * 6 * 10^-4 m^2 = 20 N
So, the force that acts on the plunger of the second syringe is 20 N. The correct answer is D. 20 N.
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