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Some students conducted a survey on some people’s weekly income:$1500,$400,$1700,$400,$175500,$500$1500,$400,$1700,$400,$175500,$500The mean of these people’s weekly income is .The median of these people’s weekly income is .Which number, mean or median, is a better way to represent these people’s weekly income?meanmedian

Question

Some students conducted a survey on some people’s weekly income:1500,1500,400,1700,1700,400,175500,175500,5001500,1500,400,1700,1700,400,175500,175500,500The mean of these people’s weekly income is .The median of these people’s weekly income is .Which number, mean or median, is a better way to represent these people’s weekly income?meanmedian

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Solution

To answer this question, we first need to calculate the mean and the median of the given data.

The mean is calculated by adding all the numbers together and then dividing by the number of numbers.

The median is the middle number when the numbers are listed in numerical order. If there is an even number of numbers, the median is the average of the two middle numbers.

Let's calculate:

The given weekly incomes are: 1500,1500, 400, 1700,1700, 400, 175500,175500, 500, 1500,1500, 400, 1700,1700, 400, 175500,175500, 500

First, let's add them all together: 1500+1500 + 400 + 1700+1700 + 400 + 175500+175500 + 500 + 1500+1500 + 400 + 1700+1700 + 400 + 175500+175500 + 500 = $360400

There are 12 numbers, so we divide 360400by12togetthemean:360400 by 12 to get the mean: 360400 / 12 = $30033.33

Next, let's find the median. First, we need to list the numbers in numerical order: 400,400, 400, 400,400, 400, 500,500, 500, 1500,1500, 1500, 1700,1700, 1700, 175500,175500, 175500

There are 12 numbers, so the median is the average of the 6th and 7th numbers: (500+500 + 500) / 2 = $500

So, the mean of these people’s weekly income is 30033.33andthemedianis30033.33 and the median is 500.

In this case, the median is a better way to represent these people’s weekly income. The reason is that the mean is greatly affected by the two extremely high incomes of $175500. These are outliers and they skew the mean, making it much higher than most of the incomes in the list. The median, on the other hand, is not affected by outliers and therefore provides a better representation of the typical income in this case.

This problem has been solved

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