Two identical trains A and B running in the opposite direction at the same speed take 2 minutes to cross each other completely. The number of bogies of A are increased from 16 to 20. How much more time would they now require to cross each other?Marks : 2Negative Marks : 0Answer here40 sec50 sec20 sec15 secClearPrevNext
Question
Two identical trains A and B running in the opposite direction at the same speed take 2 minutes to cross each other completely. The number of bogies of A are increased from 16 to 20. How much more time would they now require to cross each other?Marks : 2Negative Marks : 0Answer here40 sec50 sec20 sec15 secClearPrevNext
Solution
The time taken for two trains to cross each other is directly proportional to the length of the trains.
In the initial scenario, let's assume each train has a length equivalent to 16 bogies. So, the total length when both trains cross each other is 16 (from train A) + 16 (from train B) = 32 bogies.
They take 2 minutes (or 120 seconds) to cross each other.
Now, the number of bogies in train A is increased to 20. So, the total length when both trains cross each other now is 20 (from train A) + 16 (from train B) = 36 bogies.
Let's denote the initial time taken to cross as T1, the initial total length as L1, the new time taken to cross as T2, and the new total length as L2.
We know that T1/L1 = T2/L2 (since time is directly proportional to length).
Substituting the known values:
120 seconds / 32 bogies = T2 / 36 bogies
Solving for T2 gives us T2 = (120 seconds * 36 bogies) / 32 bogies = 135 seconds.
So, the trains would now take 135 seconds to cross each other.
The increase in time is therefore 135 seconds - 120 seconds = 15 seconds.
So, the answer is 15 sec.
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