12345678910111213#include <stdio.h> int main() { int day = 2; switch (day * 2) { case 2: printf("Tuesday "); case 4: printf("Thursday "); default: printf("Weekday "); } return 0; }
Question
12345678910111213#include <stdio.h> int main() { int day = 2; switch (day * 2) { case 2: printf("Tuesday "); case 4: printf("Thursday "); default: printf("Weekday "); } return 0; }
Solution
The code you provided is written in C language. It's a simple program that uses a switch-case statement to print out the name of a day based on the value of the variable day.
Here's a step-by-step explanation of how the code works:
-
The
mainfunction is declared. This is the entry point of the program. -
An integer variable
dayis declared and initialized with the value2. -
A switch-case statement is used. The expression inside the switch is
day * 2, which means the value ofdayis multiplied by2. Sincedayis2,day * 2equals4. -
The switch-case statement checks if the value of
day * 2matches any of the cases. In this case, it matchescase 4. -
The code inside
case 4is executed, which isprintf("Thursday ");. This prints "Thursday " to the console. -
After that, the
defaultcase is executed. This is because there are nobreakstatements after each case. Thebreakstatement is used to stop the rest of the cases from being checked and executed once a match is found. Without it, the program "falls through" to the next case, executing all the remaining cases. Thedefaultcase is executed if no other case matches, but in this case, it's executed because of the fallthrough. -
The
defaultcase prints "Weekday " to the console. -
The
return 0;statement signifies that the program has ended successfully.
So, the output of this program will be "Thursday Weekday ".
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