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12345678910111213#include <stdio.h> int main() { int day = 2; switch (day * 2) { case 2: printf("Tuesday "); case 4: printf("Thursday "); default: printf("Weekday "); } return 0; }

Question

12345678910111213#include <stdio.h> int main() { int day = 2; switch (day * 2) { case 2: printf("Tuesday "); case 4: printf("Thursday "); default: printf("Weekday "); } return 0; }

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Solution

The code you provided is written in C language. It's a simple program that uses a switch-case statement to print out the name of a day based on the value of the variable day.

Here's a step-by-step explanation of how the code works:

  1. The main function is declared. This is the entry point of the program.

  2. An integer variable day is declared and initialized with the value 2.

  3. A switch-case statement is used. The expression inside the switch is day * 2, which means the value of day is multiplied by 2. Since day is 2, day * 2 equals 4.

  4. The switch-case statement checks if the value of day * 2 matches any of the cases. In this case, it matches case 4.

  5. The code inside case 4 is executed, which is printf("Thursday ");. This prints "Thursday " to the console.

  6. After that, the default case is executed. This is because there are no break statements after each case. The break statement is used to stop the rest of the cases from being checked and executed once a match is found. Without it, the program "falls through" to the next case, executing all the remaining cases. The default case is executed if no other case matches, but in this case, it's executed because of the fallthrough.

  7. The default case prints "Weekday " to the console.

  8. The return 0; statement signifies that the program has ended successfully.

So, the output of this program will be "Thursday Weekday ".

This problem has been solved

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