How many moles of Cl- ions are present in 328 mL of a 0.244 M FeCl3 solution. Do not use scientific notation. Give your answer to 3 significant figures. Do not include units.
Question
How many moles of Cl- ions are present in 328 mL of a 0.244 M FeCl3 solution. Do not use scientific notation. Give your answer to 3 significant figures. Do not include units.
Solution
To find the number of moles of Cl- ions in the solution, we first need to find the number of moles of FeCl3.
- Convert the volume from mL to L: 328 mL = 0.328 L
- Use the molarity (M) formula, M = moles/L, to find the moles of FeCl3: (0.244 moles/L) * 0.328 L = 0.080 moles of FeCl3
- Each molecule of FeCl3 contains 3 Cl- ions, so multiply the moles of FeCl3 by 3 to find the moles of Cl-: 0.080 moles * 3 = 0.240 moles of Cl-
So, there are 0.240 moles of Cl- ions in the solution.
Similar Questions
A student takes a 60.0 mL volume from a stock solution of 0.532 mol L-1 magnesium chloride.How many moles of chloride ions, Cl−, are present in the taken volume, 60.0 mL?Enter your answer with three significant figures. Do not include units.
Iron Oxide, Fe2O3, reacts with 25 mL of 30 M Hydrochloric acid, HCl. What is the mass of Iron(III) Chloride, FeCl3 formed? Round your answer to 4 s.f. The reaction equation and relative atomic masses have been provided:Fe2O3 + 6HCl --> 2FeCl3 + 3H2O Ar:Fe = 55.8Cl = 35.5O = 16.0H = 1.0Select your answer:Select your answerOPTION ALTERNATIVE 38.72 g 44.43 g 36.35 g 10.49 g 40.58 g
27. Calculate the amount of Fe+2 ions in 500 ml Mohr’s salt solution if 10ml of this solution is titrated with 7.5ml 0.06N KMnO4 solution. (1ml 1N KMnO4= 0.05584 gm of F+2). Ans: 1.256 gm
3. If 252 grams of iron are reacted with 321 grams of chlorine gas, how many grams of FeCl3 are produced by this reaction?2Fe(s) + 3Cl2(g) → 2FeCl3(s)
100 cm3 of magnesium chloride (MgCl2) solution is made with a concentration of 1.00 mol dm–3. Calculate the amount (in mol) of chloride ions, Cl–, present in the solution.
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.