The ratio of petrol and kerosene in the container is 3:2 when 10 liters of the mixture is taken out and is replaced by the kerosene, the ratio become 2:3. Then total quantity of the mixture in the container is:
Question
The ratio of petrol and kerosene in the container is 3:2 when 10 liters of the mixture is taken out and is replaced by the kerosene, the ratio become 2:3. Then total quantity of the mixture in the container is:
Solution
Step 1: Let's assume the total quantity of the mixture in the container is x liters.
Step 2: According to the problem, the ratio of petrol to kerosene in the container is 3:2. So, the quantity of petrol is 3x/5 liters and the quantity of kerosene is 2x/5 liters.
Step 3: When 10 liters of the mixture is taken out, the quantity of petrol becomes 3x/5 - 6 liters (since petrol is 3/5 of the mixture) and the quantity of kerosene becomes 2x/5 - 4 liters (since kerosene is 2/5 of the mixture).
Step 4: The problem states that after 10 liters of the mixture is replaced by kerosene, the ratio of petrol to kerosene becomes 2:3. So, we can write the equation as (3x/5 - 6)/(2x/5 - 4 + 10) = 2/3.
Step 5: Solving the above equation, we get x = 30 liters. So, the total quantity of the mixture in the container is 30 liters.
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