The product of hydrolysis of diborane is boric acid and hydrogen gas. Here's the step by step process:

1. Diborane (B2H6) reacts with water (H2O).

2. During hydrolysis, the bonds between boron and hydrogen in diborane break.

3. The boron atoms bond with the oxygen atom in water, forming boric acid (H3BO3).

4. The hydrogen atoms from both diborane and water form hydrogen gas (H2).

So, the chemical reaction can be written as:

B2H6 + 6H2O → 2H3BO3 + 6H2

This means that for every molecule of diborane that reacts with six molecules of water, two molecules of boric acid and six molecules of hydrogen gas are produced.

Question

The product of hydrolysis of diborane is boric acid and hydrogen gas. Here's the step by step process:

1. Diborane (B2H6) reacts with water (H2O).

2. During hydrolysis, the bonds between boron and hydrogen in diborane break.

3. The boron atoms bond with the oxygen atom in water, forming boric acid (H3BO3).

4. The hydrogen atoms from both diborane and water form hydrogen gas (H2).

So, the chemical reaction can be written as:

B2H6 + 6H2O → 2H3BO3 + 6H2

This means that for every molecule of diborane that reacts with six molecules of water, two molecules of boric acid and six molecules of hydrogen gas are produced.

Knowee AI · Accepted Answer

The product of hydrolysis of diborane is boric acid and hydrogen gas. Here's the step by step process:

1. Diborane (B2H6) reacts with water (H2O).

2. During hydrolysis, the bonds between boron and hydrogen in diborane break.

3. The boron atoms bond with the oxygen atom in water, forming boric acid (H3BO3).

4. The hydrogen atoms from both diborane and water form hydrogen gas (H2).

So, the chemical reaction can be written as:

B2H6 + 6H2O → 2H3BO3 + 6H2

This means that for every molecule of diborane that reacts with six molecules of water, two molecules of boric acid and six molecules of hydrogen gas are produced.

Write the product on hydrolysis of diborane

Question

Solution

Similar Questions

Upgrade your grade with Knowee