Measurements show that the energy of a mixture of gaseous reactants increases by 104.kJ during a certain chemical reaction, which is carried out at a constant pressure. Furthermore, by carefully monitoring the volume change it is determined that −61.kJ of work is done on the mixture during the reaction.Calculate the change in enthalpy of the gas mixture during the reaction. Round your answer to 3 significant digits. kJIs the reaction exothermic or endothermic?
Question
Measurements show that the energy of a mixture of gaseous reactants increases by 104.kJ during a certain chemical reaction, which is carried out at a constant pressure. Furthermore, by carefully monitoring the volume change it is determined that −61.kJ of work is done on the mixture during the reaction.Calculate the change in enthalpy of the gas mixture during the reaction. Round your answer to 3 significant digits. kJIs the reaction exothermic or endothermic?
Solution
The change in enthalpy (ΔH) of a system can be calculated using the formula:
ΔH = q_p + w
where: q_p is the heat absorbed or released at constant pressure, and w is the work done on the system.
Given in the problem, q_p = 104 kJ (since the energy of the mixture increases, it means the system absorbed heat) and w = -61 kJ (since work is done on the mixture, it means the system does work).
Substituting these values into the formula, we get:
ΔH = 104 kJ - 61 kJ = 43 kJ
So, the change in enthalpy of the gas mixture during the reaction is 43 kJ.
Since the change in enthalpy is positive, the reaction is endothermic. This means the system absorbs heat from its surroundings during the reaction.
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