Solve the system by substitution.y, equals, 10, xy=10xy, equals, minus, 3, x, plus, 39y=−3x+39
Question
Solve the system by substitution.y, equals, 10, xy=10xy, equals, minus, 3, x, plus, 39y=−3x+39
Solution
The given system of equations is:
- y = 10x
- y = -3x + 39
Step 1: Since both equations are already solved for y, we can set them equal to each other:
10x = -3x + 39
Step 2: Solve for x by adding 3x to both sides of the equation:
10x + 3x = 39 13x = 39
Step 3: Divide both sides by 13 to solve for x:
x = 39 / 13 x = 3
Step 4: Substitute x = 3 into the first equation to solve for y:
y = 10 * 3 y = 30
So, the solution to the system of equations is x = 3 and y = 30.
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