The script prints `[1, 2, 3]`.

Here's the step-by-step explanation:

1. `l1 = [1, 2, 3]` creates a list `l1` with elements 1, 2, and 3.
2. `l2 = l1` assigns the reference of `l1` to `l2`. Now, `l1` and `l2` are pointing to the same list `[1, 2, 3]`.
3. `l1 = l1 + [4]` creates a new list by concatenating `l1` and `[4]`, and assigns the reference of this new list to `l1`. Now, `l1` is pointing to the list `[1, 2, 3, 4]`, but `l2` is still pointing to the original list `[1, 2, 3]`.
4. `print(l2)` prints the list that `l2` is pointing to, which is `[1, 2, 3]`.

Question

The script prints `[1, 2, 3]`.

Here's the step-by-step explanation:

1. `l1 = [1, 2, 3]` creates a list `l1` with elements 1, 2, and 3.
2. `l2 = l1` assigns the reference of `l1` to `l2`. Now, `l1` and `l2` are pointing to the same list `[1, 2, 3]`.
3. `l1 = l1 + [4]` creates a new list by concatenating `l1` and `[4]`, and assigns the reference of this new list to `l1`. Now, `l1` is pointing to the list `[1, 2, 3, 4]`, but `l2` is still pointing to the original list `[1, 2, 3]`.
4. `print(l2)` prints the list that `l2` is pointing to, which is `[1, 2, 3]`.

Knowee AI · Accepted Answer

The script prints `[1, 2, 3]`.

Here's the step-by-step explanation:

1. `l1 = [1, 2, 3]` creates a list `l1` with elements 1, 2, and 3.
2. `l2 = l1` assigns the reference of `l1` to `l2`. Now, `l1` and `l2` are pointing to the same list `[1, 2, 3]`.
3. `l1 = l1 + [4]` creates a new list by concatenating `l1` and `[4]`, and assigns the reference of this new list to `l1`. Now, `l1` is pointing to the list `[1, 2, 3, 4]`, but `l2` is still pointing to the original list `[1, 2, 3]`.
4. `print(l2)` prints the list that `l2` is pointing to, which is `[1, 2, 3]`.

What does this script print?l1 = [1, 2, 3]l2 = l1l1 = l1 + [4]print(l2)

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