The average of square of natural numbers from 1 to 35 is?

Sure, here is the step by step solution:

The formula for the sum of squares of first n natural numbers is n*(n+1)*(2n+1)/6.

So, the sum of squares of first 35 natural numbers is 35*(35+1)(235+1)/6 = 13685.

The average of squares of these numbers is the sum divided by the count of numbers. So, the average is 13685/35 = 391.

So, the average of square of natural numbers from 1 to 35 is 391.

Sure, to find the average of the squares of natural numbers from 1 to 35, we need to use the formula for the sum of squares of natural numbers, which is n*(n+1)*(2n+1)/6.

Step 1: Calculate the sum of squares of natural numbers from 1 to 35. Using the formula, we get 35*(35+1)(235+1)/6 = 353671/6 = 158410.

Step 2: Calculate the average. The average is the sum divided by the number of terms. So, the average is 158410/35 = 4526.

So, the average of the squares of natural numbers from 1 to 35 is 4526.