A sealed syringe contains 15.0 mL of N2 at atmospheric pressure (760 torr). If the pressure is increased to 985 torr, what is the new volume of the syringe?Multiple choice question.225 mL11.6 mL19.4 mL
Question
A sealed syringe contains 15.0 mL of N2 at atmospheric pressure (760 torr). If the pressure is increased to 985 torr, what is the new volume of the syringe?Multiple choice question.225 mL11.6 mL19.4 mL
Solution
To solve this problem, we can use Boyle's Law, which states that the pressure and volume of a gas have an inverse relationship when temperature is held constant. In other words, P1V1 = P2V2, where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume.
Step 1: Identify the knowns. P1 = 760 torr V1 = 15.0 mL P2 = 985 torr
Step 2: Plug the knowns into the equation and solve for V2. 760 torr * 15.0 mL = 985 torr * V2 11400 torrmL = 985 torr * V2 V2 = 11400 torrmL / 985 torr V2 = 11.6 mL
So, the new volume of the syringe when the pressure is increased to 985 torr is 11.6 mL.
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