f log10 2 = 0.3010, the value of log10 80 is:Choices:- 1.602 1.903 3.903 None of these

The value of log10 80 can be calculated using the properties of logarithms.

Step 1: Break down 80 into its prime factors. 80 = 2^4 * 5^1

Step 2: Use the property of logarithms log(a*b) = log(a) + log(b) to break down log10 80 into log10 2^4 + log10 5^1

Step 3: Use the property of logarithms log(a^n) = nlog(a) to further simplify to 4log10 2 + log10 5

Step 4: Substitute the given value of log10 2 = 0.3010 into the equation to get 4*0.3010 + log10 5

Step 5: To find the value of log10 5, we can use the fact that log10 10 = 1 and log10 2 = 0.3010. Since 10 = 2 * 5, we can write log10 10 = log10 2 + log10 5. Solving for log10 5 gives us log10 5 = 1 - 0.3010 = 0.6990.

Step 6: Substitute this value back into the equation to get 4*0.3010 + 0.6990 = 1.204 + 0.699 = 1.903

So, the value of log10 80 is 1.903. Therefore, the correct choice is 1.903.