The resonant frequency of a series AC circuit consisting of a 200 μH inductor, a 0.0005 μF capacitor and a 10 Ω resistance is
Question
The resonant frequency of a series AC circuit consisting of a 200 μH inductor, a 0.0005 μF capacitor and a 10 Ω resistance is
Solution
The resonant frequency (f) of a series AC circuit can be calculated using the formula:
f = 1 / (2π√(LC))
where L is the inductance and C is the capacitance.
Given that L = 200 μH = 200 x 10^-6 H and C = 0.0005 μF = 0.0005 x 10^-6 F,
we can substitute these values into the formula:
f = 1 / (2π√((200 x 10^-6 H) * (0.0005 x 10^-6 F)))
Solving this equation will give us the resonant frequency of the circuit.
Similar Questions
A coil having a resistance of 10 Ω and an inductance of 125 mH is connected in series with a 60μF capacitor across a 120 V supply. At what frequency does resonance occurs? Find the currentflowing at the resonant frequency.
A series circuit contains a 115-Ω resistor, a 0.573-H inductor, a 0.417-μF capacitor, and a time-varying source of emf providing 43.9 V. (a) What is the resonant angular frequency of the circuit? rad/s (b) What current will flow through the circuit at the resonant frequency? A
An LCR series circuit of capacitance 62.5 nF and resistance of 50 Ω, is connected to an A.C. source of frequency 2.0 kHz. For maximum value of amplitude of current in circuit, the value of inductance is ____mH.(Take π2=10)
A series RLC circuit has power factor 0.764 and impedance 182 Q at 442 Hz. (a) What's the resistance? (b) If the inductance is 25.0 mH, what's the resonant frequencv? (1 point)
In A.C. circuit in which inductance and capacitance are joined in series. Current is found to be maximum when the value of inductance is 0.5H and the value of capacitance is 8μF. The angular frequency of applied alternating voltage will be:400 Hz5000 Hz2×105 Hz500 Hz
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.