[ NOT(p AND q) AND (NOT p OR q) AND (NOT q OR q) ] AND pisQuestion 4Answera.T.b.F.c.q.d.NOT q.e.None of the Given Choices.f.p.g.NOT p.
Question
[ NOT(p AND q) AND (NOT p OR q) AND (NOT q OR q) ] AND pisQuestion 4Answera.T.b.F.c.q.d.NOT q.e.None of the Given Choices.f.p.g.NOT p.
Solution
Sure, let's break down the given expression step by step:
-
The expression is:
[ NOT(p AND q) AND (NOT p OR q) AND (NOT q OR q) ] AND p -
Let's simplify each part inside the brackets first:
NOT(p AND q): This is the negation of the conjunction ofpandq. According to De Morgan's laws, this is equivalent toNOT p OR NOT q.NOT p OR q: This is already in its simplest form.NOT q OR q: This is a tautology becauseqORNOT qis always true.
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Now, substitute the simplified parts back into the expression:
[ (NOT p OR NOT q) AND (NOT p OR q) AND true ] AND p
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Since
truedoes not affect the conjunction, we can simplify further:[ (NOT p OR NOT q) AND (NOT p OR q) ] AND p
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Distribute the
ANDinside the brackets:[(NOT p OR NOT q) AND (NOT p OR q)]
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Let's analyze the expression
(NOT p OR NOT q) AND (NOT p OR q):-
This can be simplified by considering the possible values of
pandq:- If
pis true, thenNOT pis false, so the expression depends onq. - If
qis true, thenNOT qis false, so the expression depends onp.
- If
-
The expression
(NOT p OR NOT q) AND (NOT p OR q)simplifies toNOT p.
-
-
Now, substitute back into the main expression:
[ NOT p ] AND p
-
This simplifies to:
NOT p AND p
-
NOT p AND pis always false becausepandNOT pcannot be true at the same time.
Therefore, the answer is:
b. F.
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