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[ NOT(p AND q) AND (NOT p OR q) AND (NOT q OR q) ] AND pisQuestion 4Answera.T.b.F.c.q.d.NOT q.e.None of the Given Choices.f.p.g.NOT p.

Question

[ NOT(p AND q) AND (NOT p OR q) AND (NOT q OR q) ] AND pisQuestion 4Answera.T.b.F.c.q.d.NOT q.e.None of the Given Choices.f.p.g.NOT p.

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Solution

Sure, let's break down the given expression step by step:

  1. The expression is: [ NOT(p AND q) AND (NOT p OR q) AND (NOT q OR q) ] AND p

  2. Let's simplify each part inside the brackets first:

    • NOT(p AND q): This is the negation of the conjunction of p and q. According to De Morgan's laws, this is equivalent to NOT p OR NOT q.
    • NOT p OR q: This is already in its simplest form.
    • NOT q OR q: This is a tautology because q OR NOT q is always true.
  3. Now, substitute the simplified parts back into the expression:

    • [ (NOT p OR NOT q) AND (NOT p OR q) AND true ] AND p
  4. Since true does not affect the conjunction, we can simplify further:

    • [ (NOT p OR NOT q) AND (NOT p OR q) ] AND p
  5. Distribute the AND inside the brackets:

    • [(NOT p OR NOT q) AND (NOT p OR q)]
  6. Let's analyze the expression (NOT p OR NOT q) AND (NOT p OR q):

    • This can be simplified by considering the possible values of p and q:

      • If p is true, then NOT p is false, so the expression depends on q.
      • If q is true, then NOT q is false, so the expression depends on p.
    • The expression (NOT p OR NOT q) AND (NOT p OR q) simplifies to NOT p.

  7. Now, substitute back into the main expression:

    • [ NOT p ] AND p
  8. This simplifies to:

    • NOT p AND p
  9. NOT p AND p is always false because p and NOT p cannot be true at the same time.

Therefore, the answer is:

b. F.

This problem has been solved

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