What will be the output of the following Python code?class A: def __init__(self, x= 1): self.x = xclass der(A): def __init__(self,y = 2): super().__init__() self.y = ydef main(): obj = der() print(obj.x, obj.y)main()Error, the syntax of the invoking method is wrongThe program runs fine but nothing is printed1 01 2
Question
What will be the output of the following Python code?class A: def init(self, x= 1): self.x = xclass der(A): def init(self,y = 2): super().init() self.y = ydef main(): obj = der() print(obj.x, obj.y)main()Error, the syntax of the invoking method is wrongThe program runs fine but nothing is printed1 01 2
Solution 1
The output of the Python code will be "1 2".
Here's the step by step explanation:
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Class A is defined with an initializer method that sets the attribute x to 1 by default.
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Class der is defined as a subclass of A. Its initializer method first calls the initializer of A (using super().init()), which sets x to 1. Then it sets the attribute y to 2 by default.
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The main function creates an instance of der (which is also an instance of A due to inheritance), and then prints the values of x and y.
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Since no arguments are passed when creating the der object, x and y take their default values, which are 1 and 2 respectively.
So, when the main function is called, it prints "1 2".
Solution 2
The output of the given Python code will be "1 2".
Here's the step by step explanation:
-
Class A is defined with an initializer method that sets the attribute x to 1 by default.
-
Class der is defined as a subclass of A. Its initializer method first calls the initializer of A (using super().init()), which sets x to 1. Then it sets the attribute y to 2 by default.
-
The main function creates an instance of der (which is also an instance of A due to inheritance), and then prints the values of x and y.
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Since no arguments are passed when creating the der object, x and y take their default values, which are 1 and 2 respectively.
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Therefore, the output of the code is "1 2".
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