Pick the average time complexity for finding out height of Binary tree
Question
Pick the average time complexity for finding out height of Binary tree
Solution
The average time complexity for finding out the height of a Binary tree is O(n).
Here's the step by step explanation:
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Start from the root node of the binary tree.
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Traverse all nodes of the tree using any traversal method (in-order, pre-order, or post-order). This is because to find the height of the tree, we need to visit every node to find its depth in the tree. The height of the tree is the maximum depth among all nodes.
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For each node, calculate its depth, which is the length of the path from the root to that node. The depth of the root node is 0. For any other node, its depth is one more than the depth of its parent node.
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Keep track of the maximum depth encountered while traversing the tree. This maximum depth is the height of the binary tree.
Since we are visiting all nodes of the tree once, the time complexity of this process is O(n), where n is the number of nodes in the tree.
Similar Questions
What is the average case time complexity for finding the height of the binary tree?Optionsh = O(log n)h = O(nlogn) h = O(loglogn)h = O(n)
The average depth of a binary search tree is:*O(n^0.5)O(n)O(log n)O(n log n)
What is the average time complexity for searching an element in a binary search tree?Group of answer choicesO(1)O(n)O(log n)Depends on the tree structure
The maximum height of a binary search tree is O(log n), where n is the number of nodes.Group of answer choicesTrueFalse
what is height of complete binary tree
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