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1. A wire of length 1.0m moves with a speed of 10m/s perpendicular to a magnetic field. If the emf induced in the wire is 1.0V, the magnitude of the magnetic field is

Question

  1. A wire of length 1.0m moves with a speed of 10m/s perpendicular to a magnetic field. If the emf induced in the wire is 1.0V, the magnitude of the magnetic field is
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Solution

The magnitude of the magnetic field can be found using Faraday's law of electromagnetic induction, which states that the induced emf in a circuit is equal to the rate of change of magnetic flux through the circuit.

In this case, the wire is moving perpendicular to the magnetic field, so the area swept out by the wire is changing. The magnetic flux through the wire is given by the product of the magnetic field strength (B), the length of the wire (l), and the perpendicular distance the wire has moved (d).

The rate of change of this flux is then B * l * (d/dt), where d/dt is the speed of the wire.

Setting this equal to the induced emf and solving for B gives:

B = emf / (l * d/dt)

Substituting the given values:

B = 1.0 V / (1.0 m * 10 m/s) = 0.1 T

So the magnitude of the magnetic field is 0.1 Tesla.

This problem has been solved

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