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Part of an ANOVA table is shown below.  Source of VariationSum ofSquaresDegrees ofFreedomMeanSquare FBetween Treatments180  3  Within Treatments (Error)    Total48018  at .05 alpha, The conclusion of the test is that the meansGroup of answer choicesNo answer text provided.are always equal to fiftyare not equalmay be equal

Question

Part of an ANOVA table is shown below.  Source of VariationSum ofSquaresDegrees ofFreedomMeanSquare FBetween Treatments180  3  Within Treatments (Error)    Total48018  at .05 alpha, The conclusion of the test is that the meansGroup of answer choicesNo answer text provided.are always equal to fiftyare not equalmay be equal

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Solution

The question seems to be asking for the conclusion of an ANOVA (Analysis of Variance) test given the provided table. However, the table is incomplete. Specifically, the "Mean Square" for "Between Treatments" and the "Sum of Squares" and "Degrees of Freedom" for "Within Treatments (Error)" are missing.

In an ANOVA test, we compare the means of different groups to determine if they are equal or not. The null hypothesis (H0) is that all group means are equal, while the alternative hypothesis (H1) is that at least one group mean is different.

To make a conclusion, we need to calculate the F statistic and compare it to the critical F value at a given significance level (alpha). The F statistic is calculated as the Mean Square Between Treatments divided by the Mean Square Within Treatments.

If the calculated F statistic is greater than the critical F value, we reject the null hypothesis and conclude that the means are not equal. If the F statistic is less than or equal to the critical F value, we fail to reject the null hypothesis and conclude that the means may be equal.

Without the missing values, we cannot calculate the F statistic and therefore cannot make a conclusion.

This problem has been solved

Similar Questions

Part of an ANOVA table is shown below.  Source of VariationSum ofSquaresDegrees ofFreedomMeanSquare FBetween Treatments180  3  Within Treatments (Error)    Total48018   If at a 5% level of significance, we want to determine whether or not the means of the populations are equal, the critical value of F isGroup of answer choices5.863.292.5319.48

The ANOVA procedure is a statistical approach for determining whether or not the means of two or more samples are equalGroup of answer choicesFalseTrue

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A researcher has collected the following sample data.   351232The coefficient of variation isGroup of answer choices72.66%264%81.24%27.66%

A hypothesis was tested at an α = 0.05 significance level. Review the table below and complete the sentence that follows:Table 1 ScoreSum of squaresdfMean squareFSig. (p)Between groups11.57125.7867.8180.02Within groups154.2346240.740Total165.805626Based on the information presented in Table 1, the decision is taken to __________.Group of answer choicesReject the null hypothesisAccept the null hypothesisReject the alternative hypothesisAccept the alternative hypothesis

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