What will be the output of the following code?#include <iostream>using namespace std;int main() { int n; for (n = 5; n > 0; n--) { cout << n; if (n == 3) break; } return 0;}Options: Pick one correct answer from below54354543253

The correct answer is 543.

Here's the step by step explanation:

1. The code starts with a for loop where the variable 'n' is initialized to 5.

2. The condition for the loop is n > 0, which means the loop will continue as long as 'n' is greater than 0.

3. Inside the loop, the value of 'n' is printed and then decremented by 1 (n--).

4. The if statement checks if 'n' is equal to 3. If it is, the break statement is executed and the loop is immediately terminated.

5. So, the output of the code will be the numbers 5, 4, and 3 printed consecutively without any spaces or newlines between them, hence 543. After printing 3, the break statement is executed and the loop ends.