A wire of length 314 cm carrying current of 14 A is bent to form a circle. The magnetic moment of the coil is _________ A – m2. [ Given π = 3.14]
Question
A wire of length 314 cm carrying current of 14 A is bent to form a circle. The magnetic moment of the coil is _________ A – m2. [ Given π = 3.14]
Solution
To find the magnetic moment of the coil, we first need to find the area of the circle formed by the wire.
Step 1: Find the radius of the circle The length of the wire is equal to the circumference of the circle. We can use the formula for the circumference of a circle, which is 2πr, where r is the radius of the circle.
314 cm = 2πr Divide both sides by 2π to solve for r: r = 314 cm / 2π = 50 cm
Step 2: Find the area of the circle We can use the formula for the area of a circle, which is πr².
Area = π * (50 cm)² = 7850 cm²
Step 3: Find the magnetic moment The magnetic moment (M) of a coil is given by the product of the current (I) and the area (A) of the coil.
M = I * A M = 14 A * 7850 cm² = 109,900 A.cm²
However, the standard unit for magnetic moment is A.m². To convert from cm² to m², we divide by 10,000 (since 1 m² = 10,000 cm²).
M = 109,900 A.cm² / 10,000 = 10.99 A.m²
So, the magnetic moment of the coil is approximately 10.99 A.m².
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