A Centre-tap transformer rectifier is required to be designed for AC-DC rectification with a transformation ratio 6:1:1 and energized from AC input of 230V 50Hz supply. with no filter capacitor. The load resistor is approximately 5.4 Ohm. The peak value of the load current would be:Select one:
Question
A Centre-tap transformer rectifier is required to be designed for AC-DC rectification with a transformation ratio 6:1:1 and energized from AC input of 230V 50Hz supply. with no filter capacitor. The load resistor is approximately 5.4 Ohm. The peak value of the load current would be:Select one:
Solution
To find the peak value of the load current, we first need to find the peak value of the secondary voltage.
Step 1: Calculate the secondary voltage The transformation ratio is 6:1:1, which means the primary voltage is divided by 6 to get the secondary voltage. So, the secondary voltage is 230V/6 = 38.33V.
Step 2: Calculate the peak value of the secondary voltage The peak value of a sinusoidal waveform is √2 times the RMS value. So, the peak value of the secondary voltage is 38.33V * √2 = 54.19V.
Step 3: Calculate the peak value of the load current The load current is the secondary voltage divided by the load resistance. So, the peak value of the load current is 54.19V / 5.4 Ohm = 10.03A.
So, the peak value of the load current would be approximately 10.03A.
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