Tn is the nth term of a sequence S. The terms T2 – T1, T3 – T2, T4 – T3 … are in AP. If T3 = 40, T5 = 104 and T7 = 200, the value of T10 is ______.
Question
Tn is the nth term of a sequence S. The terms T2 – T1, T3 – T2, T4 – T3 … are in AP. If T3 = 40, T5 = 104 and T7 = 200, the value of T10 is ______.
Solution
This problem involves a sequence where the differences between consecutive terms form an arithmetic progression (AP).
Step 1: Let's denote the common difference of the AP as 'd'. So, we have T3 - T2 = d, T4 - T3 = d + d = 2d, T5 - T4 = 3d, and so on.
Step 2: From the given, we know T5 - T3 = 104 - 40 = 64 and T7 - T5 = 200 - 104 = 96.
Step 3: According to our pattern, T5 - T3 = 2d and T7 - T5 = 2d. So, we have 2d = 64 and 2d = 96. This is a contradiction, so there seems to be a mistake in the problem statement.
If the problem statement is correct, then the differences between consecutive terms do not form an arithmetic progression.
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