The last two digits in the expansion of 520^20 can be found using the concept of cyclicity.

The cyclicity of 0 is 0, and the cyclicity of 2 is 4 (2, 4, 8, 6).

Since 20 is a multiple of 4, we consider the 4th number in the cycle of 2, which is 6.

However, since the base number (520) ends in 0, no matter what the power is, the last digit will always be 0.

So, the last two digits in the expansion of 520^20 are 60.

Question

The last two digits in the expansion of 520^20 can be found using the concept of cyclicity.

The cyclicity of 0 is 0, and the cyclicity of 2 is 4 (2, 4, 8, 6).

Since 20 is a multiple of 4, we consider the 4th number in the cycle of 2, which is 6.

However, since the base number (520) ends in 0, no matter what the power is, the last digit will always be 0.

So, the last two digits in the expansion of 520^20 are 60.

Knowee AI · Accepted Answer

The last two digits in the expansion of 520^20 can be found using the concept of cyclicity.

The cyclicity of 0 is 0, and the cyclicity of 2 is 4 (2, 4, 8, 6).

Since 20 is a multiple of 4, we consider the 4th number in the cycle of 2, which is 6.

However, since the base number (520) ends in 0, no matter what the power is, the last digit will always be 0.

So, the last two digits in the expansion of 520^20 are 60.

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