Time taken by A, B, C to reach a same destination is in ratio 6:4:3. What will be the ration of speed at which they cover the distance?A)Sat Dec 30 1899 07:24:14 GMT+0521 (India Standard Time)B)Sat Dec 30 1899 09:26:16 GMT+0521 (India Standard Time)C)Sat Dec 30 1899 11:30:12 GMT+0521 (India Standard Time)D)None of these.

The question seems to be a bit mixed up, but I'll try to answer the part that makes sense.

The time taken by A, B, C to reach the same destination is in the ratio 6:4:3. To find the ratio of their speeds, we need to understand that speed is inversely proportional to time. This means that if one person takes less time to cover a distance, their speed is higher and vice versa.

So, if the time ratio is 6:4:3, the speed ratio will be the inverse of this, which is 1/6 : 1/4 : 1/3.

To simplify this ratio, we can find the least common multiple (LCM) of 6, 4, and 3, which is 12.

Then, we divide the LCM by each of the numbers in the time ratio to get the speed ratio:

For A, it's 12/6 = 2 For B, it's 12/4 = 3 For C, it's 12/3 = 4

So, the ratio of their speeds is 2:3:4.

The question seems to be a bit mixed up, but I'll try to answer the part that makes sense.

The time taken by A, B, C to reach the same destination is in the ratio 6:4:3. To find the ratio of their speeds, we need to understand that speed is inversely proportional to time. This means that if one person takes less time to travel a certain distance, their speed is higher.

So, if the time ratio is 6:4:3, the speed ratio will be the inverse of this, which is 1/6 : 1/4 : 1/3.

To simplify this ratio, we can find the least common multiple (LCM) of 6, 4, and 3, which is 12.

Then, we multiply each part of the ratio by 12 to get the speed ratio:

(12/6) : (12/4) : (12/3) = 2 : 3 : 4

So, the ratio of their speeds is 2:3:4.