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Select the correct answerWhat will be the output of the following Python code?>>> ct={k: 'C' + str(k) for k in range(4)}>>> ctOptionsAn exception is thrown{0: '0', 1: '1', 2: '2', 3: '3’}{0: 'C', 1: 'C', 2: 'C', 3: 'C'}{0: 'C0', 1: 'C1', 2: 'C2', 3: 'C3'}

Question

Select the correct answerWhat will be the output of the following Python code?>>> ct={k: 'C' + str(k) for k in range(4)}>>> ctOptionsAn exception is thrown{0: '0', 1: '1', 2: '2', 3: '3’}{0: 'C', 1: 'C', 2: 'C', 3: 'C'}{0: 'C0', 1: 'C1', 2: 'C2', 3: 'C3'}

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Solution

The output of the given Python code will be {0: 'C0', 1: 'C1', 2: 'C2', 3: 'C3'}.

Here's the step by step explanation:

  1. The code is creating a dictionary using dictionary comprehension.

  2. The keys of the dictionary are numbers from 0 to 3 (as specified by the range function).

  3. The values of the dictionary are strings, which are created by concatenating 'C' with the string representation of the key.

  4. So, for key 0, the value will be 'C' + str(0) = 'C0'. Similarly, for key 1, the value will be 'C' + str(1) = 'C1', and so on.

  5. Therefore, the final dictionary will be {0: 'C0', 1: 'C1', 2: 'C2', 3: 'C3'}.

This problem has been solved

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