There is an integer n > 5 such that 2^n − 1 is prime. Can you prove this?

Given:(1) If n is an even number, then 5n + 2 is always an even number.(2) If n is an integer larger than 1, then 2^n − 1 is always a prime number.Select one of the following choices:Question 16Answera.(1) and (2) are True.b.(1) is True and (2) is False.c.(1) and (2) are False.d.(1) is False and (2) is True.

If n is prime then for every x 0<x<n, (xn-1 % n)=1 according to?infoYou have max 2 attempts to score in this question.Attempts left:2/2OptionsThis problem has only one correct answerFermat’s theoremWilson’s theoremMiller rabinNone of the above

A prime number is an integer greater or equal to 2 that is only divisible by 1 and by itself. The first few primes are: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47 …N is a prime if and only if it is not divisible evenly by any of the numbers from 2 to N−1. Let’s implement this decision as a function.

A prime number is an integer greater or equal to 2 that is only divisible by 1 and by itself. The first few primes are: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47 …N is a prime if and only if it is not divisible evenly by any of the numbers from 2 to N−1. Let’s implement this decision as a function.In the same program numbers.cpp, add a functionbool isPrime(int n);The function should return true if n is a prime, otherwise return false. Change the main function to test your new code.

Which one of the following numbers is NOT a prime number?