Since the natural abundance of various isotopes are detected by mass spectrometry, one would expect...Group of answer choicesA 1:1 ratio corresponding to the amount of 12C and 13C in a sample.A 1:1 ratio corresponding to the amount of 12C and 14C in a sample.A 1:1 ratio corresponding to the amount of 1H and 2H in a sample.A 1:1 ratio corresponding to the amount of 79Br and 81Br in a sample that contains one bromine atom.
Question
Since the natural abundance of various isotopes are detected by mass spectrometry, one would expect...Group of answer choicesA 1:1 ratio corresponding to the amount of 12C and 13C in a sample.A 1:1 ratio corresponding to the amount of 12C and 14C in a sample.A 1:1 ratio corresponding to the amount of 1H and 2H in a sample.A 1:1 ratio corresponding to the amount of 79Br and 81Br in a sample that contains one bromine atom.
Solution
The correct answer is "A 1:1 ratio corresponding to the amount of 79Br and 81Br in a sample that contains one bromine atom."
Here's why:
Mass spectrometry is a technique that separates ions based on their mass-to-charge ratio. In the context of isotopes, it can be used to determine the relative abundance of different isotopes in a sample.
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12C and 13C: Carbon-12 is much more abundant than Carbon-13. The natural abundance of 12C is about 98.9% while that of 13C is about 1.1%. So, we would not expect a 1:1 ratio.
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12C and 14C: Carbon-14 is a radioactive isotope of carbon with a half-life of about 5,730 years. Its abundance is extremely low compared to 12C. So, we would not expect a 1:1 ratio.
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1H (protium) and 2H (deuterium): Protium is much more abundant than deuterium. The natural abundance of protium is about 99.98% while that of deuterium is about 0.02%. So, we would not expect a 1:1 ratio.
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79Br and 81Br: These are the two stable isotopes of bromine and they are relatively close in natural abundance. The natural abundance of 79Br is about 50.69% and that of 81Br is about 49.31%. So, if a sample contains one bromine atom, mass spectrometry would detect a roughly 1:1 ratio of these two isotopes.
Similar Questions
The presence of a bromine atom in a molecule will produce a mass spectrum with an (M+2)+• peak that is approximately equal to the intensity of the molecular ion peak becauseSelect answer from the options belowthe 79Br isotope has a higher natural abundance than 81Br isotope.molecules with the 79Br and 81Br isotopes tend to fragment easily.the 79Br and 81Br isotopes have almost equal natural abundance.the 81Br isotope has a higher natural abundance than 79Br isotope.
Recognize common isotopes and their uses.
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