1 pointWhat is the output of the following code?i = 2while True:    if i%3 == 0:        break    print(i)    i += 22 4 6 8 10 ...2 32 4Error

The output of the given code will be "2 4". Here's the step by step explanation:

1. The variable i is initialized with the value 2.
2. The while True: statement starts an infinite loop.
3. Inside the loop, the if i%3 == 0: statement checks if the current value of i is divisible by 3.
4. If i is divisible by 3, the break statement is executed, which terminates the loop.
5. If i is not divisible by 3, the print(i) statement is executed, which prints the current value of i.
6. The i += 2 statement increments the value of i by 2.
7. The loop then repeats from step 3.

In the first iteration, i is 2, which is not divisible by 3, so 2 is printed and i is incremented to 4. In the second iteration, i is 4, which is also not divisible by 3, so 4 is printed and i is incremented to 6. In the third iteration, i is 6, which is divisible by 3, so the loop is terminated and no more numbers are printed. Therefore, the output of the code is "2 4".