What is the output of the following Java code:Code:class HackerEarth { int getValue() { int returnValue = 10; try { String[] Languages = { "Try block", "Try block is running" }; System.out.println(Languages[1]); } catch (Exception e) { System.out.println("Catch Block :" + returnValue); return returnValue; } finally { returnValue += 10; System.out.println("Finally Block :" + returnValue); } return returnValue; } public static void main(String args[]) { HackerEarth var = new HackerEarth(); System.out.println("Main Block:" + var.getValue()); }}
Question
What is the output of the following Java code:Code:class HackerEarth { int getValue() { int returnValue = 10; try { String[] Languages = { "Try block", "Try block is running" }; System.out.println(Languages[1]); } catch (Exception e) { System.out.println("Catch Block :" + returnValue); return returnValue; } finally { returnValue += 10; System.out.println("Finally Block :" + returnValue); } return returnValue; } public static void main(String args[]) { HackerEarth var = new HackerEarth(); System.out.println("Main Block:" + var.getValue()); }}
Solution
The output of the given Java code will be:
Try block is running
Finally Block :20
Main Block:20
Here's the step by step explanation:
-
The
mainmethod is the entry point of the program. It creates an instance of theHackerEarthclass and calls thegetValuemethod on it. -
Inside the
getValuemethod, an integerreturnValueis declared and initialized with the value10. -
Then a
tryblock is executed. Inside this block, an array of StringsLanguagesis declared and initialized with two elements. The second element of this array is printed to the console. Since there is no error in this block, thecatchblock is skipped. -
After the
tryandcatchblocks, thefinallyblock is executed. Inside this block, the value ofreturnValueis incremented by10, making it20. This new value is then printed to the console. -
After the
finallyblock, the method returns the value ofreturnValue, which is20. This value is printed to the console in themainmethod.
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