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What is the value stored in the given variable when returned by the below function call?int myCount = countLetters("Coding in C++ is fun.", 'c');int countLetters(string phrase, char letter) { int numLetters = 0; for (int i = 0; i < phrase.length(); i++) { if (phrase[i] == letter) { numLetters++; } } return numLetters;}

Question

What is the value stored in the given variable when returned by the below function call?int myCount = countLetters("Coding in C++ is fun.", 'c');int countLetters(string phrase, char letter) { int numLetters = 0; for (int i = 0; i < phrase.length(); i++) { if (phrase[i] == letter) { numLetters++; } } return numLetters;}

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Solution

The function countLetters is case-sensitive. It counts the number of occurrences of a specific character in a string. In the function call countLetters("Coding in C++ is fun.", 'c'), it is looking for the lowercase letter 'c'.

In the string "Coding in C++ is fun.", the lowercase 'c' appears only once (in the word "Coding"). Therefore, the function will return 1.

So, the value stored in the variable myCount will be 1.

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